How can you find the nth node from the end of a linked list in two passes?

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How can you find the nth node from the end of a linked list in two passes?

To find the nth node from the end of a linked list in two passes, you can follow the below steps:

1. In the first pass, traverse the linked list and count the total number of nodes present in the list. Let's say the count is 'count'.

2. Calculate the position of the nth node from the end using the formula:
position = count - n + 1. Here, 'n' represents the position from the end that we want to find.

3. Reset the current pointer to the head of the linked list.

4. In the second pass, traverse the linked list until the position of the nth node from the end is reached. Move the current pointer 'position - 1' times.

5. Once the current pointer reaches the desired position, it will be pointing to the nth node from the end of the linked list.

6. Return the value or perform any required operations on the nth node from the end.

By following these steps, you can find the nth node from the end of a linked list in two passes.